Write a program that asks the user to enter a value n, and then computes (1+
1/2 +
1/3 +···+
1/n
)−
ln(n). The ln function is log in the math module.

import math


# get the value of n from the user

n = int(input("Enter a value for n: "))


# initialize the sum to 0

sum = 0


# loop through the numbers from 1 to n

for i in range(1, n+1):

  # add 1/i to the sum

  sum += 1/i


# compute the result

result = sum - math.log(n)


# print the result

print(result)

This program first imports the math module and gets the value of n from the user. It then initializes a sum variable to 0 and loops through the numbers from 1 to n, adding 1/i to the sum. It then computes the result using the formula given and prints the result.

If you run the program, it will ask you to enter a value for n, and then it will compute and print the result. For example, if you enter 10 when prompted, you might see something like:

Enter a value for n: 10
1.5574077246549023

This is the result of the computation for the given value of n.